For which of the following pairs of complexes | vedclass

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(C) The crystal field splitting energy $\Delta_0$ depends on the oxidation state of the metal,the nature of the ligand,and the principal quantum numbe

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$a, b, c, d$

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(C) The crystal field splitting energy $\Delta_0$ depends on the oxidation state of the metal,the nature of the ligand,and the principal quantum number of the metal ($3d$ vs $4d$ vs $5d$).$(a). [Cr(H_2O)_6]^{2+}$ vs $[Cr(H_2O)_6]^{3+}$: $\Delta_0$ increases with the oxidation state of the metal. Since $Cr^{3+}$ has a higher charge than $Cr^{2+}$,$\Delta_0(II) > \Delta_0(I)$.$(b). [Fe(H_2O)_6]^{3+}$ vs $[Fe(CN)_6]^{3-}$: $\Delta_0$ increases with the field strength of the ligand. $CN^-$ is a stronger field ligand than $H_2O$,so $\Delta_0(II) > \Delta_0(I)$.$(c). [Fe(CN)_6]^{3-}$ vs $[Ru(CN)_6]^{3-}$: $\Delta_0$ increases down a group as the principal quantum number increases $(3d  \Delta_0(I)$.$(d). [NiF_6]^{4-}$ vs $[NiF_6]^{2-}$: $\Delta_0$ increases with the oxidation state of the metal. $Ni^{4+}$ has a higher charge than $Ni^{2+}$,so $\Delta_0(II) > \Delta_0(I)$.Therefore,all pairs satisfy the condition $\Delta_0(II) > \Delta_0(I)$.

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$I$	$II$
$(a). [Cr(H_2O)_6]^{2+}$	$[Cr(H_2O)_6]^{3+}$
$(b). [Fe(H_2O)_6]^{3+}$	$[Fe(CN)_6]^{3-}$
$(c). [Fe(CN)_6]^{3-}$	$[Ru(CN)_6]^{3-}$
$(d). [NiF_6]^{4-}$	$[NiF_6]^{2-}$

For which of the following pairs of complexes is the crystal field splitting energy $\Delta_0$ for $II > \Delta_0$ for $I$? $I$ $II$ $(a). [Cr(H_2O)_6]^{2+}$ $[Cr(H_2O)_6]^{3+}$ $(b). [Fe(H_2O)_6]^{3+}$ $[Fe(CN)_6]^{3-}$ $(c). [Fe(CN)_6]^{3-}$ $[Ru(CN)_6]^{3-}$ $(d). [NiF_6]^{4-}$ $[NiF_6]^{2-}$